
$6 \,\mu \mathrm{F}$ and $12\, \mu \mathrm{F}$ are in series, their equivalent $=4\, \mu \mathrm{F}$
Now $4 \,\mu F(2 \text { and } 2\, \mu F)$ and $8\, \mu F$ in series
$=\frac{3}{8}\, \mu F$
And $4\, \mu \mathrm{F}(12 \& 6\, \mu \mathrm{F})$ and $4\, \mu \mathrm{F}$ in parallel $=4+4=8\, \mu \mathrm{F}$
$8\, \mu \mathrm{F}$ in series with $1\, \mu \mathrm{F}=\frac{1}{8}+1 \Rightarrow \frac{8}{9}\, \mu \mathrm{F}$
Now $C_{e q}=\frac{8}{9}+\frac{8}{3}=\frac{32}{9}$
$C_{eq}$ of circuit $=\frac{32}{9}$
With $C-\frac{1}{C_{e q}}=\frac{1}{C}+\frac{9}{32}=1 \Rightarrow C=\frac{32}{23}$



Which of the following statement($s$) is(are) correct in SI units?
$(A)$ When $x=q$, the magnitude of the electric field at $O$ is zero.
$(B)$ When $x=-q$, the magnitude of the electric field at $O$ is $\frac{q}{6 \pi \in_0 a^2}$.
$(C)$ When $x=2 q$, the potential at $O$ is $\frac{7 q}{4 \sqrt{3} \pi \in_0 a}$.
$(D)$ When $x=-3 q$, the potential at $O$ is $\frac{3 q}{4 \sqrt{3} \pi \in_0 a}$.

