MCQ
Figure shows graph between stress and strain for a uniform wire at two different femperatures. Then
- A$T_2 > T_1$
- ✓$T_1 > T_2$
- C$T_1 = T_2$
- DNone of these
✓
Answer
Correct option: B.
$T_1 > T_2$
b
(a)
(a)
From the graph we can see young's modulus is less for $T_1$ as compared to $T_2$ ( $Y=$ slope of stress-strain curve)
As $T$ increases $Y$ decreases
So $T_1 > T_2$
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