Question
Find distance between point $Q(3,-7)$ and point $R(3,3)$
Solution: Suppose $Q\left(x_1, y_1\right)$ and point $R\left(x_2, y_2\right)$
$x_1=3, y_1=-7 \text { and } x_2=3, y_2=3$
Using distance formula,
$ d(Q, R)=\sqrt{\square}$
$\therefore d(Q, R)=\sqrt{\square-100}$
$\therefore d(Q, R)=\sqrt{\square}$
$\therefore d(Q, R)=\square $

Answer

Suppose $Q\left(x_1, y_1\right)$ and point $R\left(x_2, y_2\right)$
$x_1=3, y_1=-7 \text { and } x_2=3, y_2=3$
Using distance formula,
$ d(Q, R)=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$
$=\sqrt{(3-3)^2-[3-(-7)]^2}$
$=\sqrt{0^2+(10)^2}$
$\therefore d(Q, R)=\sqrt{0-100}$
$\therefore d(Q, R)=\sqrt{100}$
$\therefore d(Q, R)=10 $

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