Question
Find distance between point $Q(3,-7)$ and point $R(3,3)$
Solution: Suppose $Q\left(x_1, y_1\right)$ and point $R\left(x_2, y_2\right)$
$x_1=3, y_1=-7 \text { and } x_2=3, y_2=3$
Using distance formula,
$ d(Q, R)=\sqrt{\square}$
$\therefore d(Q, R)=\sqrt{\square-100}$
$\therefore d(Q, R)=\sqrt{\square}$
$\therefore d(Q, R)=\square $
Solution: Suppose $Q\left(x_1, y_1\right)$ and point $R\left(x_2, y_2\right)$
$x_1=3, y_1=-7 \text { and } x_2=3, y_2=3$
Using distance formula,
$ d(Q, R)=\sqrt{\square}$
$\therefore d(Q, R)=\sqrt{\square-100}$
$\therefore d(Q, R)=\sqrt{\square}$
$\therefore d(Q, R)=\square $



