Question
Find the equivalent capacitance of the network shown in the figure, when each capacitor is of $1\mu\text{F}$. When the ends $X$ and $Y$ are connected to a $6 V$ battery, find out $(i)$ The charge and $(ii)$ The energy stored in the network.
✓
Answer
The equivalent setup is:
Here ? $A =$ ?${B }(A B$ are at the same potential$)$ so the bridge capacitor can be removed.
- $\text{Q} = \text{CV} = 6 \mu\text{c}.$
- $\text{U} = \frac{1}{2}\text{qV} = 18 \mu\text{J}.$
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