Five equal resistances each of resistance $R$ are connected as shown in the figure. A battery of $V\, volts$ is connected between $A$ and $B$. The current flowing in $AFCEB$ will be
A$\frac{{3V}}{R}$
B$\frac{V}{2R}$
C$\frac{V}{{R}}$
D$\frac{{2V}}{R}$
AIPMT 2004, Medium
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B$\frac{V}{2R}$
b $R _{\text {eq. }}$ of wheatstone bridge $= R$ current in the circuit .
$\Rightarrow V = I R \Rightarrow I =\frac{ V }{ R }$
current in one branch of the wheatstone bridge $=\frac{ V }{2 R }$
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