The capacities and connection of five capacitors are shown in the adjoining figure. The potential difference between the points $A$ and $B$ is $60\;volts$. Then the equivalent capacity between $A$ and $B$ and the charge on $5\,\mu F$ capacitance will be respectively
Medium
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(d) The given circuit can be redrawn ass follows
Equivalent capacitance of the circuit ${C_{AB}} = 4\,\mu F$
Charge given by the battery $Q = {C_{eq}}V = 4 \times 60 = 240\,\mu C$
Charge in $5\,µF$ capacitor $Q' = \frac{5}{{(10 + 5 + 9)}} \times 240 = 50\,\mu C$
Equivalent capacitance of the circuit ${C_{AB}} = 4\,\mu F$
Charge given by the battery $Q = {C_{eq}}V = 4 \times 60 = 240\,\mu C$
Charge in $5\,µF$ capacitor $Q' = \frac{5}{{(10 + 5 + 9)}} \times 240 = 50\,\mu C$
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