For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration. The change in the collector current when the

Q: For a transistor, the current amplification factor is $0.8.$ The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6 $m A$ is

$\alpha=0.8 \Rightarrow \beta=\frac{0.8}{(1-0.8)}=4$ Also $\beta=\frac{\Delta i_c}{\Delta i_b} \Rightarrow \Delta i_c=\beta \times \Delta i_b=4 \times 6=24 \mathrm{~mA}$.

MCQ

CBSE - English Medium

For a transistor, the current amplification factor is $0.8.$ The transistor is connected in common emitter configuration. The change in the collector current when the base current changes by 6 $m A$ is

A$6 mA$
B$4.8 mA$
C$24 mA$
D$8 mA$

[Haryana CET 1991]

STD 12 Science
JEE physics
Electronics
NCERT

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