For the given cyclic process $CAB$ as shown for a gas, the work done is ..... $J$
JEE MAIN 2019, Easy
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Work done $=$ Area of loop
$= \frac{1}{2} (4) (5)$
$= 10\, J$
$= \frac{1}{2} (4) (5)$
$= 10\, J$
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