The latent heat of vaporisation of water is $2240\, J/gm$. If the work done in the process of expansion of $1 \,g$ is $168 \,J$, then increase in internal energy is ....... $J$
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(c) $\Delta Q = \Delta U + \Delta W$$ \Rightarrow \Delta U = \Delta Q - \Delta W = 2240 - 168 = 2072\;J$.
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For a thermodynamic process $\delta Q = -50$ $calorie$ and $W = -20$ $calorie$ . If the initial internal energy is $-30$ $calorie$ then final internal energy will be ....... $calorie$
$1c{m^3}$ of water at its boiling point absorbs $540$ calories of heat to become steam with a volume of $1671c{m^3}$.If the atmospheric pressure = $1.013 \times {10^5}N/{m^2}$ and the mechanical equivalent of heat = $4.19J/calorie$, the energy spent in this process in overcoming intermolecular forces is ..... $cal$
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