- A$\frac{1}{9}$
- ✓$\frac{1}{81}$
- C$\frac{1}{27}$
- D$\frac{1}{3}$
at equilibrium $\frac{{2P}}{9}$ $\frac{{P}}{9}$
$\left\{ \begin{gathered}
a + \frac{{2P}}{9} + \frac{P}{9} = P \hfill \\
a = \frac{{2P}}{3} \hfill \\
\end{gathered} \right.$
$K_{p}=\frac{\left(\frac{2 P}{9}\right)^{2}\left(\frac{P}{9}\right)}{\left(\frac{2 P}{3}\right)^{2}}=\frac{P}{81}$
$\boxed{\frac{{{K_p}}}{P} = \frac{1}{{81}}}$
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Statement $I:$ Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green.
Statement $II:$ The green colour observed is due to the formation of copper(I) metaborate.
In the light of the above statements, choose the most appropriate answer from the options given below :