$I ^{-}+ ClO _3^{-}+ H _2 SO _4 \longrightarrow Cl ^{-}+ HSO _4^{-}+ I _2$
The correct statement(s) in the balanced equation is/are:
$(A)$ Stoichiometric coefficient of $HSO _4^{-}$is 6 .
$(B)$ lodide is oxidized.
$(C)$ Sulphur is reduced.
$(D)$ $H _2 O$ is one of the products.
Hence, $I ^{-}$is oxidised to $I _2$
Coefficient of $HSO _4^{-}=6$
and $H _2 O$ is one of the product.
Hence $(A),(B),(D)$
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$Br_{2(l)} + Cl_{2(g)} \rightarrow 2BrCl_{(g)}$
are $30\ kJ\ mol^{-1}$ and $105\ J\ K^{-1} mol^{-1}$ respectively. The temperature at which the reaction will be in equilibrium is ............... $\mathrm{K}$
