Fountains usually seen in gardens are generated by a wide pipe with an enclosure at one end having many small holes. Consider one such fountain which is produced by a pipe of internal diameter $2$ $cm$ in which water flows at a rate $3$ $ms^{^{-1}}$. The enclosure has $100$ holes each of diameter $0.05$ $cm$. The velocity of water coming out of the holes ids ( in $ms^{^{-1}}$)
Medium
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Volume flow rate is same
So $\pi\left(1 \times 10^{-2}\right)^{2} \times 3$
$=100 \times \pi\left(\frac{0.05 \times 10^{-2}}{2}\right)^{2} \times V$
$\pi \times 10^{-4} \times 3$
$=100 \times \pi \times 1 / 4 \times 25 \times 10^{-8} \times V$
$V=\frac{4 \times 3}{25} \times 100=48$
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