Four capacitors are connected as shown in the figure. Their capacities are indicated in the figure. The effective capacitance between points $x$ and $y$ is (in $\mu F$)
A$\frac{5}{6}$
B$\frac{7}{6}$
C$\frac{8}{3}$
D$2$
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C$\frac{8}{3}$
c (c) The given circuit can be simplified as follows
$==>$ ${C_{xy}} = \frac{2}{3} + 2 = \frac{8}{3}\,\mu F$
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