Four condensers each of capacity $4\,\mu F$ are connected as shown in figure. ${V_P} - {V_Q} = 15\,volts$. The energy stored in the system is......$ergs$
Medium
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(b) Total capacitance of given system ${C_{eq}} = \frac{8}{5}\,\mu F$
$U = \frac{1}{2}{C_{eq}}{V^2} = \frac{1}{2} \times \frac{8}{5} \times {10^{ - 6}} \times 225 = 180 \times {10^{ - 6}}\,J$
$ = 180 \times {10^{ - 6}} \times {10^7}\,erg = 1800\,erg$
$U = \frac{1}{2}{C_{eq}}{V^2} = \frac{1}{2} \times \frac{8}{5} \times {10^{ - 6}} \times 225 = 180 \times {10^{ - 6}}\,J$
$ = 180 \times {10^{ - 6}} \times {10^7}\,erg = 1800\,erg$
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