The combined capacity of the parallel combination of two capacitors is four times their combined capacity when connected in series. This means that
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(a) ${C_p} = 4{C_s}$ $==>$ $({C_1} + {C_2}) = 4\frac{{{C_1}{C_2}}}{{({C_1} + {C_2})}}$
$==>$ ${({C_1} - {C_2})^2} = 0$ $==>$ ${C_1} = {C_2}$
$==>$ ${({C_1} - {C_2})^2} = 0$ $==>$ ${C_1} = {C_2}$
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