Four identical point masses $'m'$ joined by light string of length $'l'$ arrange such that they form square frame. Centre of table is coincide with centre of arrangment. If arrangement rotate with constant angular velocity $'\omega '$ , find out tension in each string
A$\frac{{m{\omega ^2}l}}{4}$
B$m{\omega ^2}l/2$
C$m{\omega ^2}l/\sqrt 2 $
D$m{\omega ^2}l$
Medium
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B$m{\omega ^2}l/2$
b $T\sqrt 2 = \frac{{m{\omega ^2}l}}{{\sqrt 2 }}$
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