Four resistances of $15\; \Omega, 12\; \Omega, 4 \;\Omega$ and $10\; \Omega$ respectively in cyclic order to form Wheats tone's network. The resistance that is to be connected in parallel with the resistance of $10\; \Omega$ to balance the network is .................. $\Omega$
JEE MAIN 2020, Medium
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Let the resistance to be connected is $\mathrm{R}$. For balanced wheatstone bridge.
$15 \times 4=12 \times \frac{10 \mathrm{R}}{10+\mathrm{R}}$
$\Rightarrow \mathrm{R}=10 \Omega$
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