MCQ
Four rods of same material and having the same cross section and length have been joined, as shown. The temperature of junction of four rods will be........ $^oC$
  • A
    $20$
  • B
    $30$
  • $45$
  • D
    $60$

Answer

Correct option: C.
$45$
c
$\frac{{{\rm{KA}}(90 - \theta )}}{l} = \frac{{{\rm{KA}}(\theta  - 30)}}{l} + \frac{{{\rm{KA}}(\theta  - {\rm{0}})}}{l} + \frac{{{\rm{KA}}(\theta  - 60)}}{l}$

$90-\theta=3 \theta-90^{\circ}$

$\theta=45^{\circ}$ $C$

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