In an hydrogen atom, the electron revolves around the nucleus in an orbit of radius $0.53 \times {10^{ - 10}}\,m$. Then the electrical potential produced by the nucleus at the position of the electron is......$V$
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(c) $V = 9 \times {10^9} \times \frac{Q}{r} = 9 \times {10^9} \times \frac{{( + 1.6 \times {{10}^{ - 19}})}}{{0.53 \times {{10}^{ - 10}}}}= 27.2\,V$
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