MCQ
$f(x) = [\sin x] \cos \left( {\frac{\pi }{{[x - 1]}}} \right)$ નો પ્રદેશગણ ....... થાય (જ્યા $[.]$ = $G.I.F.$)
- A$R$
- B$R -\{1\}$
- C$R -(1, 2)$
- D$R -[1, 2)$
$[\mathrm{x}] \neq 1$
$x \notin 1$
$x \notin[1,2)$
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$f(x)=\left\{\begin{array}{cc}x+1, & x < 0 \\|x-1|, & x \geq 0\end{array} \text { and } g(x)=\left\{\begin{array}{cc}x+1, & x < 0 \\1, & x \geq 0\end{array}\right. \text {. }\right.$
મુજબ વ્યાખ્યાયિત વિધેયો છે. તો $(gof)(x)$ એ $........$