Question
  1. Give reasons for the following:
i. $Mn ^{3+}$ is a good oxidizing agent.
ii. $E ^{\circ} m ^{2+} / M$ values are not regular for first row transition metals. (3d series)
iii. Although ' $F$ ' is more electronegative then ' O ', the highest Mn fluoride is $Mnf _4$, whereas the highest oxide is $Mn _2 O _7$.
  1. Complete the following equations:
$\text{2CrO}_{4}^{2}+\text{2H}^{+}\rightarrow$

$\text{KMnO}_{4}\xrightarrow{heat}$

Answer

  1.  
i. $Mn ^{3+}\left(3 d^4\right)$ good electron acceptor as resulting species is more stable $\left(3 d^5\right)$
ii. The $E^{\circ}\left( M ^{2+} / M \right)$ values are not regular which can be explained from the irregular variation of ionisation enthalpies $\left(\Delta iH _1+\Delta i H _2\right)$, sublimation enthalpies and hydration enthalpies.
iii. Due to multiple bond formation ability of oxygen with Mn in $Mn _2 O _7$.
  1.  
  1. $2CrO_4^{2-} + 2H^+ \rightarrow Cr_2O_7^{2-}+ H_2O.$
  2. $2KMnO_4$​​​​​​​ $\xrightarrow{Heat} K_2MnO_4 + MnO_2 + O_2.$

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