MCQ
Given the reaction between $2$ gases represented by $A_2$ and $B$ to give the compound $AB_{(g)}$ 

$A_{2(g)} + B_{2(g)} \rightleftharpoons  2AB_{(g)}$

At equilibrium, the concentration of $A_2= 3.0 \times 10^{-3} \, M,$ of $B_2= 4.2 \times 10^{-3} \, M,$ of $AB= 2.8 \times 10^{-3} \, M,$

If the reaction takes place in a sealed vessel at $527^o C,$ then the value of $K_c$ will be

  • A
    $2$
  • B
    $1.9$
  • $0.62$
  • D
    $4.5$

Answer

Correct option: C.
$0.62$
c
$A_{2(g)}+B_{2(g)} \rightleftharpoons 2 A B_{(g)}$

$K_{c}=\frac{[A B]^{2}}{\left[A_{2}\right]\left[B_{2}\right]}$

$=\frac{\left(2.8 \times 10^{-3}\right)^{2}}{\left(3.0 \times 10^{-3}\right)\left(4.2 \times 10^{-3}\right)}$

$=\frac{2.8 \times 2.8}{3.0 \times 4.2}=0.62$

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