c
Velocity at ground (means zero height) is non- zero therefore one is incorrect and velocity versus height is non-linear therefore two is also incorrect.

\(v^{2}=2 g h\)

\(v \frac{d v}{d h}=2 g=c o n s t\)

\(\frac{d v}{d h}=\frac{c o n s t a n t}{v}\)

Here we can see slope is very high when velocity is low therefore at Maximum height the slope should be very large which is in option \(3\) and as velocity increases slope must decrease there for option \(3\) is correct.