\({(2)^2}R\left[ {\frac{1}{{{2^2}}} - \frac{1}{{{4^2}}}} \right] = \frac{{3R}}{4}\)
For hydrogen atoms, \(\frac{1}{\lambda } = R\left[ {\frac{1}{{n_1^2}} - \frac{1}{{n_2^2}}} \right]\)
\(\frac{{3R}}{4} = R\left[ {\frac{1}{{n_1^2}} - \frac{1}{{n_2^2}}} \right]\,\frac{1}{{n_1^2}} - \frac{1}{{n_2^2}} = \frac{3}{4}\)
\(n_1 = 1\) and \(n_2 = 2.\)
$(C= 3 \times 10^8 \,ms^{-1},N_A = 6.02 \times 10^{23} mol^{-1}).$