$\begin{aligned} \lambda_1 &=16 \lambda_{2} \\ \therefore \frac{1}{\lambda_1} &=\frac{1}{16} \times \frac{1}{\lambda_2} \end{aligned}$

$\therefore X\left(\frac{1}{n_1^2}-\frac{1}{ n _2^2}\right) \times Z _1^2=\frac{1}{16} K\left(-\frac{1}{ n _1^2}-\frac{1}{ n _2^2}\right) \times Z_2^2$

$\therefore i ^2=\frac{1}{16} \times Z _2^2 \quad \therefore Z _2=4 \quad \therefore Be ^{3+}$ આયન