Therefore, weight of $HCl$ in $1\, ml$ of solution = specific gravity $x \,49\, \%$
$=1.41 \times 49 / 100$
$=0.6909\, g / ml$
Weight of $HCl$ in $1000\, ml$ of solution $=0.6909 \times 1000=690.9\, g$
Molarity = weight of $HCl$ in $1000\,ml /$ mol.weight of $HCl$
$=690.9 / 36.4$
$=18.9 \,M$
(પાણી માટે $K_f=1.86\, K\, kg, mol^{-1}$ અને ઇથિલીન ગ્લાયકોલનું આણ્વિય દળ $= 62\, g\, mol^{-1}).$