The rate of flow of heat, $(R)$
$=\frac{K A \Delta T}{1} \propto \frac{A}{1}$
Therefore $\frac{R_{1}}{R_{2}}=\frac{A_{1}}{A_{2}} \times \frac{l_{2}}{l_{1}}=$
$\left(\frac{1}{2}\right)^{2} \times \frac{1}{2}=\frac{1}{8}$
or $\quad R_{1}: R_{2}=1: 8$

$(i)$ The maximum intensity of the emitted radiation will occur at frequency $v /3$
$(ii)$ The maximum intensity of the emitted radiation will occur at frequency $3v $
$(iii)$ The total energy of emitted radiation will become $81\,E$
$(iv)$ The total energy of emitted radiation will become $27\,E$