A body takes $5$ minutes for cooling from ${50^o}C$ to ${40^o}C.$ Its temperature comes down to ${33.33^o}C$ in next $5$ minutes. Temperature of surroundings is ....... $^oC$
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(b) In first case $\frac{{50 - 40}}{5} = K\left[ {\frac{{50 + 40}}{2} - {\theta _0}} \right]$….$(i)$
In second case $\frac{{40 - 33.33}}{5} = K\left[ {\frac{{40 + 33.33}}{2} - \theta } \right]$….$(ii)$
By solving ${\theta _0} = {20^o}C$.
In second case $\frac{{40 - 33.33}}{5} = K\left[ {\frac{{40 + 33.33}}{2} - \theta } \right]$….$(ii)$
By solving ${\theta _0} = {20^o}C$.
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