How many H-atoms are present in 0.046 ,g of ethanol - Vidyadip

MCQ

How many $H-$atoms are present in $0.046 \,g $ of ethanol

A
$6 \times {10^{20}}$
B
$1.2 \times {10^{21}}$
C
$3 \times {10^{21}}$
✓
$3.6 \times {10^{21}}$

✓

Answer

Correct option: D.

$3.6 \times {10^{21}}$

d
(d) Mol. wt of ${C_2}{H_5}OH = 2 \times 12 + 5 + 16 + 1 = 64$

$\because 48\,g\,{C_2}{H_5}OH$ has $H$ atom $ = 6 \times {N_A}$

$\therefore $ $0.046\,g\,\,{C_2}{H_5}OH$ has $H$ atoms $ = \frac{{6 \times 6.02 \times {{10}^{23}} \times 0.046}}{{46}}$$ = 3.6 \times {10^{21}}$

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