Question
How will you convert:
- Propyne into propanone?
- Secondary butyl bromide into but-2-ene?
$\text{HC}\equiv\text{C}-\text{CH}_3+\text{H}_2\text{O}\xrightarrow{\text{H}_2\text{SO}_4}\\ \ \ \ \ \ \ \ \ _\text{Propyne}\\\text{CH}_2=\text{C}-\text{CH}_3\rightleftharpoons\text{CH}_3-\text{C}-\text{CH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ||\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{O}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{\text{Acetone (or propanone)}}$
$\text{CH}_3-\text{CH}-\text{CH}_2-\text{CH}_3+\text{KOH(alc.)}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{Br}\\ \ \ \ \ \ \ \ \ \ _{\text{Sec. butyl bromide}}\\\ \ \ \ \ \ \ \ \ \ _\text{(2-Bromobutane)}\\\text{CH}_3-\text{CH}=\text{CH}-\text{CH}_3+\text{KBr}+\text{H}_2\text{O}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{\text{But-2-ene}}$
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