MCQ
$(i)$ What is the work done by the porter when he climbs up a height of $10m (g = 10\ ms^{-2})?$
- A$5\ kJ^2$
- B$50\ kJ$
- C$100\ kJ^2$
- ✓$5\ kJ$
✓
Answer
Correct option: D.
$5\ kJ$
The work done by the potter is defined as the product of the force and the displacement.
Work done $=$ force $\times$ displacement
$= m \times g \times 10 ($ Since force $=$ mass $\times$ gravity$)$
$= 50 \times 10 \times 10$
$= 5KJ$
Work done $=$ force $\times$ displacement
$= m \times g \times 10 ($ Since force $=$ mass $\times$ gravity$)$
$= 50 \times 10 \times 10$
$= 5KJ$
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