Question
If $3 \sin \theta = 4 \cos \theta,$ then $sec \theta = ?$

Answer

$ 3 \sin \theta=4 \cos \theta \quad \ldots . . \text { [Given] }$
$\therefore \frac{\sin \theta}{\cos \theta}=\frac{4}{3}$
$\therefore \tan \theta=\frac{4}{3} $
We know that,
$1+\tan ^2 \theta=\sec ^2 \theta$
$\therefore 1+\left(\frac{4}{3}\right)^2=\sec ^2 \theta$
$\therefore 1+\frac{16}{9}=\sec ^2 \theta$
$\therefore \sec ^2 \theta=\frac{9+16}{9}$
$\therefore \sec ^2 \theta=\frac{25}{9}$
$\therefore \sec \theta=\frac{5}{3}$ [Taking square root of both sides]

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