If a cyclist moving with a speed of $4.9\, m/s$ on a level road can take a sharp circular turn of radius $4 \,m$, then coefficient of friction between the cycle tyres and road is
A$0.41$
B$0.51$
C$0.61$
D$0.71$
AIIMS 1999, Easy
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C$0.61$
c (c)$\mu = \frac{{{v^2}}}{{rg}} = \frac{{{{(4.9)}^2}}}{{4 \times 9.8}} = 0.61$
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