If a load of $9$ $kg$ is suspended on a wire, the increase in length is $4.5\, mm$. The force constant of the wire is
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(b) $F = Kx \Rightarrow K = \frac{F}{x} = \frac{{9 \times 9.8}}{{4.5 \times {{10}^{ - 3}}}} = 1.96 \times {10^4}N/m$
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