Time period of a pendulum
$T=2 \pi \sqrt{\frac{l}{g}} \text { or } T_2 \sqrt{\frac{1}{g}}$
If $g$ becomes $4$ times. I must also be increased by $4$ times to keep $T$ constant.

$y_1 = \sin \left( {\omega t + \frac{\pi }{3}} \right)$ and $y_2 = \sin \omega t$ is :


