If a slab of insulating material $4 \times {10^{ - 3}}\,m$ thick is introduced between the plates of a parallel plate capacitor, the separation between plates has to be increased by $3.5 \times {10^{ - 3}}\,m$ to restore the capacity to original value. The dielectric constant of the material will be
Diffcult
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(b) $K = \frac{t}{{t - d'}} = \frac{{4 \times {{10}^{ - 3}}}}{{4 \times {{10}^{ - 3}} - 3.5 \times {{10}^{ - 3}}}} = 8$
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