Question
If $A=\left[\begin{array}{lll}0 & 4 & 9 \\ 8 & 3 & 7\end{array}\right], B=\left[\begin{array}{lll}7 & 3 & 8 \\ 1 & 4 & 9\end{array}\right]$ find the value of $B-5 A$
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Answer
$\begin{aligned} & B-5 A=\left[\begin{array}{lll}7 & 3 & 8 \\ 1 & 4 & 9\end{array}\right]-5\left[\begin{array}{lll}0 & 4 & 9 \\ 8 & 3 & 7\end{array}\right] \\ & =\left[\begin{array}{lll}7 & 3 & 8 \\ 1 & 4 & 9\end{array}\right]-\left[\begin{array}{ccc}0 & 20 & 45 \\ 40 & 15 & 35\end{array}\right] \\ & =\left[\begin{array}{ccc}7 & -17 & -37 \\ -39 & -11 & -26\end{array}\right]\end{aligned}$
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