MCQ
If an electron in hydrogen atom jumps from third orbit to second orbit, the frequency of the emitted radiation is given by ( $c$ is speed of light)
- A$\frac{3 R c}{29}$
- ✓$\frac{5 R c}{36}$
- C$\frac{7 R c}{36}$
- D$\frac{8 R c}{31}$
✓
Answer
Correct option: B.
$\frac{5 R c}{36}$
b
(b)
(b)
$\frac{1}{\lambda}=R\left(\frac{1}{2^2}-\frac{1}{3^2}\right)$
$f=R_0 c\left(\frac{1}{4}-\frac{1}{9}\right)$
$f=\frac{R c 5}{36}=\frac{5 R c}{36}$
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