If charge on left plane of the $5\ \mu F$ capacitor in the circuit segment shown in the figure is $-20\ \mu C$, the charge on the right plate of $3\ \mu F$ capacitor is.......$ \mu C$
Diffcult
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Charge on right should be positive and
$\mathrm{q}_{1}+\mathrm{q}_{2}=20 \mu \mathrm{C}$ and $\frac{\mathrm{q}_{1}}{3}=\frac{\mathrm{q}_{2}}{4}$
$\Rightarrow \frac{\mathrm{q}_{1}}{\mathrm{q}_{2}}=\frac{3}{4}$
$\Rightarrow \mathrm{q}_{1}=\frac{3}{7} \times 20=\frac{60}{7}$
$=8.57 \mu \mathrm{C}$
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