A spherical drop of capacitance $1\,\,\mu F$ is broken into eight drops of equal radius. Then, the capacitance of each small drop is ......$\mu F$
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(c) Using $C = {n^{1/3}}c$ $==>$ $c = \frac{C}{{{n^{1/3}}}} = \frac{C}{{{{(8)}^{1/3}}}} = \frac{C}{2}$$ = \frac{1}{2}\,\mu F$
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