If ${C_V} = 4.96cal/mole\, K$, then increase in internalenergy when temperature of $2$ moles of this gas is increased from $340 K$ to $342 K$ ....... $cal$
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(b) $\Delta U = \mu {C_V}\Delta T = 2 \times 4.96 \times (342 - 340) = 19.84\;cal$
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