MCQ
If $f(x) = ({\log _{\cot x}}\tan x){({\log _{\tan x}}\cot x)^{ - 1}},$ then $f'(2) = $
- A$2$
- ✓$0$
- C${1 \over 2}$
- D$-2$
$ = {({\log _{\cot x}}{(\cot x)^{ - 1}})^2} \Rightarrow f'(x) = 0$ .
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