The root mean square speed of the molecules of a diatomic gas is $v$. When the temperature is doubled, the molecules dissociate into two atoms. The new root mean square speed of the atom is
A$\sqrt 2 v$
B$v$
C$2v$
D$4v$
Medium
Download our app for free and get started
C$2v$
c $V _{ rms }=\sqrt{\frac{3 RT }{ M }}.$
According to problem $T$ will become $2 T$ and $M$ will become $M / 2$ so the value of $V _{ rms }$ will increase by $\sqrt{4}=2$ times
i.e, new root mean square velocity will be $2 \; v$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A mixture of one mole of monoatomic gas and one mole of a diatomic gas (rigid) are kept at room temperature $\left(27^{\circ} \mathrm{C}\right)$. The ratio of specific heat of gases at constant volume respectively is:
Three vessels of equal volume contain gases at the same temperature and pressure. The first vessel contains neon (monoatomic), the second contains chlorine (diatomic) and third contains uranium hexafloride (polyatomic). Arrange these on the basis of their root mean square speed $\left(v_{ ms }\right)$ and choose the correct answer from the options given below:
A balloon carries a total load of $185\; {kg}$ at normal pressure and temperature of $27^{\circ} {C}$. What load will the balloon carry on rising to a height at which the barometric pressure is $45\; {cm}$ of ${Hg}$ and the temperature is $-7^{\circ} {C}$. Assuming the volume constant? (in ${kg}$)