If number of molecules of ${H_2}$ are double than that of ${O_2}$, then ratio of kinetic energy of hydrogen and that of oxygen at $300 \,K$ is
A$1:1$
B$1:2$
C$2:1$
D$1:16$
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A$1:1$
a $K.E.$ is a function of temperature.
so, $\frac{{{E_{{H_2}}}}}{{{E_{{O_2}}}}} = \frac{1}{1}$
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