MCQ
If the distance between a point source and screen is doubled, then intensity of light on the screen will become
- AFour times
- BDouble
- CHalf
- ✓One-fourth
✓
Answer
Correct option: D.
One-fourth
d
(d)Intensity $ \propto \frac{1}{{{{{\rm{(Distance)}}}^{\rm{2}}}}}$
(d)Intensity $ \propto \frac{1}{{{{{\rm{(Distance)}}}^{\rm{2}}}}}$
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