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A capacitor is connected to a battery of voltage $V$. Now a di electric slab of dielectric constant $k$ is completely inserted between the plates, then the final charge on the capacitor will be
Two equal charges $q$ of opposite sign separated by a distance $2a$ constitute an electric dipole of dipole moment $p$. If $P$ is a point at a distance $r$ from the centre of the dipole and the line joining the centre of the dipole to this point makes an angle $\theta $ with the axis of the dipole, then the potential at $P$ is given by $(r > > 2a)$ (Where $p = 2qa$)
Two point charges $-Q$ and $+Q / \sqrt{3}$ are placed in the xy-plane at the origin $(0,0)$ and a point $(2,0)$, respectively, as shown in the figure. This results in an equipotential circle of radius $R$ and potential $V =0$ in the $xy$-plane with its center at $(b, 0)$. All lengths are measured in meters.
A $2\, \mu F$ capacitor $C _{1}$ is first charged to a potential difference of $10\, V$ using a battery.Then the battery is removed and the capacitor is connected to an uncharged capacitor $C _{2}$ of $8\, \mu F$. The charge in $C _{2}$ on equilibrium condition is $\ldots\,\mu C$. (Round off to the Nearest Integer)