If the velocity of sound in air is $336 m/s$. The maximum length of a closed pipe that would produce a just audible sound will be
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(b) Minimum audible frequency $= 20 Hz$.
$ \Rightarrow $ $\frac{v}{{4l}} = 20 \Rightarrow l = \frac{{336}}{{4 \times 20}} = 4.2$$m$
$ \Rightarrow $ $\frac{v}{{4l}} = 20 \Rightarrow l = \frac{{336}}{{4 \times 20}} = 4.2$$m$
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