If three resistors of resistance 2 ,Omega, 4 ,Omega and 5 ,Omega are connected in parallel then the total resistance of the combination will be

Q: If three resistors of resistance $2 \,\Omega$, $4 \,\Omega$ and $5 \,\Omega$ are connected in parallel then the total resistance of the combination will be

a $\frac{1}{{{R_{eq}}}} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}} + \frac{1}{{{R_3}}}$ $ = \frac{1}{2} + \frac{1}{4} + \frac{1}{5}$ $ = \frac{{19}}{{20}}$ $ \Rightarrow $ ${R_{eq}} = \frac{{20}}{{19}}\,\Omega $

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

If three resistors of resistance $2 \,\Omega$, $4 \,\Omega$ and $5 \,\Omega$ are connected in parallel then the total resistance of the combination will be

A$\frac{{20}}{{19}}\,\Omega $
B$\frac{{19}}{{20}}\,\Omega $
C$\frac{{19}}{{10}}\,\Omega $
D$\frac{{10}}{{19}}\,\Omega $

Easy

STD 11 Science
JEE
STD 12 - 3. current electricity
Physics

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