MCQ
If $\vec{a}$ is a nonzero vector of magnitude $^{\prime} a^{\prime}$ and $\lambda$ a nonzero scalar, then $\lambda \,\,\vec{a}$ is unit vector if
- A$\lambda=1$
- ✓$a=\frac{1}{|\lambda|}$
- C$a =|\lambda|$
- D$\lambda=-1$
Now, $|\lambda \vec{a}|=1$
$\Rightarrow|\lambda||\vec{a}|=1$
$\Rightarrow|\vec{a}|=\frac{1}{|\lambda|} \quad[\lambda \neq 0]$
$\Rightarrow a=\frac{1}{|\lambda|}$ $[|\vec{a}|=a]$
Hence, vector $\lambda \vec{a}$ is a unit vector if $a=\frac{1}{|\lambda|}$
The correct answer is $B$
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