MCQ
If $y$ represents pressure and $x$ represents velocity gradient, then the dimensions of $\frac{d^2 y}{d x^2}$ are
  • A
    $\left[ ML ^{-1} T ^{-2}\right]$
  • B
    $\left[ M ^2 L ^{-2} T ^{-2}\right]$
  • $\left[ ML ^{-1} T ^0\right]$
  • D
    $\left[ M ^2 L ^{-2} T ^{-4}\right]$

Answer

Correct option: C.
$\left[ ML ^{-1} T ^0\right]$
c
(c)

$\frac{d^2 y}{d x^2}$ will have dimensions of $\frac{y}{x^2}$

$y \rightarrow$ pressure, $x \rightarrow$ velocity gradient

$x \rightarrow \frac{V}{L} \Rightarrow \frac{ LT ^{-1}}{ L } \Rightarrow T ^{-1}$

$\frac{y}{x^2}=\frac{ ML ^{-1} T ^{-2}}{ T ^{-2}} \Rightarrow\left[ ML ^{-1}\right]$

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